I need to run g++ compiled program and get exit status. My code in nodejs:
import pty from "node-pty";
...
ptyProcess.write("exec /var/www/a.out\r\n'");
What I found:
$! is the PID of the last process sent to the background
$? is the exit code of the last process
It means. I can do in terminal: /var/www/a.out && echo $? - result, running program and in the end 0 (Success exit code). Hovewer, exec don't allow to run any commands after it, as once a.out is done, exec closes.
Problem is, I am making web c++ compiler & debugger, and I want to give exec output to user (web page) to debug his written code... Once exec is done, he don't get root to whole terminal. If I use without exec, then after program is done, he can get root@server:~# .. If something is unclear, please ask in comments and I will try to explain better.
UPDATE. OK seems I can use /var/www/a.out && echo $? && exit, it is fine when program ends successfully, however if I try to press CTRL+C or CTRL+Z, I can break command and get root. With exec when you press these combinations, you don't get root.
UPDATE 2. Okay, so I ended with this:
trap '' 2 3 20 && /var/www/a.out && echo $? && exit\r\n
trap disables CTRL combinations:
SIGINT=CTRL-C
SIGQUIT=CTRL-\
SIGTSTP=CTRL-Z
